A presidential election was held in Rhode Island on November 21, 1804, as part of the 1804 United States presidential election. The Democratic-Republican Party's ticket of incumbent president Thomas Jefferson and former New York governor George Clinton was elected unanimously. The Federalist Party did not nominate electors. Jefferson won the national election in a landslide over the de facto Federalist candidate, Charles Cotesworth Pinckney.
General election Summary Rhode Island chose four electors on a statewide general ticket. Nineteenth-century election laws required voters to elect the members of the Electoral College individually, rather than as a block. This sometimes resulted in small differences in the number of votes cast for electors pledged to the same presidential nominee, if some voters did not vote for all the electors nominated by a party. The following table shows the result for the leading Democratic-Republican elector to give an approximate sense of the statewide popular vote.
Results + 1804 United States presidential election in Rhode Island Party Candidate Votes Democratic-Republican James Aldrich 1,312 Democratic-Republican James Helme 1,311 Democratic-Republican Benjamin Remington 1,309 Democratic-Republican Constant Taber 1,308 ≈1,312
Results by county + 1804 United States presidential election in Rhode Island by county County Thomas JeffersonDemocratic-Republican Total Votes % Bristol 38 100.00 38 Kent 138 100.00 138 Newport 345 100.00 345 Providence 575 100.00 575 Washington 216 100.00 216 TOTAL 1,312 100.00 1,312
See also United States presidential elections in Rhode Island
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